Domm goes to the store and buys 3 apples....

#1ODommPosted 3/24/2013 10:00:07 PM
If there is 10 inches of snow on the ground, and he drank the night before, should he go to class? Or sleep in and play Halo.

Show your work
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#2Cpt_of_IndustryPosted 3/24/2013 10:02:41 PM
One class is about $80.
A trip to the emergency room is $100

Assuming you will hurt yourself in the snow, you are saving $20 by staying home, plus halo.

The answer is "$20 plus halo."
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#3metalclashPosted 3/24/2013 10:10:34 PM
A trip to the emergency room can be a lot more than $100
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#4jesse_skaterPosted 3/24/2013 10:15:30 PM
Best Answer

y = -0.2x + 12x + 11
y - 11 = -0.2(x - 60x)

complete the square
y - 11 + (-0.2)(-60/2) = -0.2(x - 6x + (-60/2))
y - 11 - 180 = -0.2(x - 30)
y - 191 = -0.2(x - 30)
This is the form of a parabola with vertex (30,191).

The x term is squared so the parabola opens either up or down.
a. The -0.2 tells you that the parabola opens down.
=============
Found the problem--misplaced a decimal point.

b. -0.2x+12x + 11 = 0
Use the quadratic formula to solve
ax+bx+c=0
where
a=-0.2
b=12
c=11

x = [-b √(b-4ac)] / (2a)
= [-(12) √((12) - 4(-0.2)(11))] / 2(-0.2)
= [-12 √(152.8)] / -0.4
= 30 -30.903

x₊ = 30 + -30.903 ≅ -1 invalid
x₋ = 30 - -30.903 ≅ 61

Ticket sales increase until day 30, then decrease.

c. Tickets will stop selling during day 61, so ticket sales start on day 1, and stop 60 days later.

d. & e. y' = -0.4x + 12 = 0
-0.4x = -12
x = 30
Min/max occurs on day 30

y" = -0.4 < 0 so on day 30 ticket sales peak.

f. Ticket sales peak at 191 on day 30.

h. The solutions in this case are x=61 and x=-1. A quadratic equation always has two solutions (although the two may be identical).

i. x=-1 is an invalid solution because the day can't be negative.
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#5Demigod_ElessarPosted 3/24/2013 10:28:33 PM
There are ten inches of snow on the ground... and your school isn't closed?

We only have like 5-6 inches here (granted, it's still coming down, and the roads are very messed up currently, and just about every school within 30 miles around us is closed tomorrow (high schools and colleges).

Anyway, I wouldn't worry about it. Save yourself the headache of having to clear off and defrost your vehicle, and risk accident by going to school (especially if you're drunk/hangover'd). Also, you're probably saving some gas money in the process. So stay home, sleep in, and play Halo.

I'm on vacation this week from work, so for once, I can actually enjoy being snowed in.
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#6BlueRunway05Posted 3/24/2013 10:31:23 PM
jesse_skater posted...
Best Answer

y = -0.2x + 12x + 11
y - 11 = -0.2(x - 60x)

complete the square
y - 11 + (-0.2)(-60/2) = -0.2(x - 6x + (-60/2))
y - 11 - 180 = -0.2(x - 30)
y - 191 = -0.2(x - 30)
This is the form of a parabola with vertex (30,191).

The x term is squared so the parabola opens either up or down.
a. The -0.2 tells you that the parabola opens down.
=============
Found the problem--misplaced a decimal point.

b. -0.2x+12x + 11 = 0
Use the quadratic formula to solve
ax+bx+c=0
where
a=-0.2
b=12
c=11

x = [-b &#8730;(b-4ac)] / (2a)
= [-(12) &#8730;((12) - 4(-0.2)(11))] / 2(-0.2)
= [-12 &#8730;(152.8)] / -0.4
= 30 -30.903

x&#8330; = 30 + -30.903 &#8773; -1 invalid
x&#8331; = 30 - -30.903 &#8773; 61

Ticket sales increase until day 30, then decrease.

c. Tickets will stop selling during day 61, so ticket sales start on day 1, and stop 60 days later.

d. & e. y' = -0.4x + 12 = 0
-0.4x = -12
x = 30
Min/max occurs on day 30

y" = -0.4 < 0 so on day 30 ticket sales peak.

f. Ticket sales peak at 191 on day 30.

h. The solutions in this case are x=61 and x=-1. A quadratic equation always has two solutions (although the two may be identical).

i. x=-1 is an invalid solution because the day can't be negative.


Believe it or not, this is dumb math to me.
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#7TMoney650Posted 3/24/2013 11:11:59 PM
BlueRunway05 posted...
jesse_skater posted...
Best Answer

y = -0.2x + 12x + 11
y - 11 = -0.2(x - 60x)

complete the square
y - 11 + (-0.2)(-60/2) = -0.2(x - 6x + (-60/2))
y - 11 - 180 = -0.2(x - 30)
y - 191 = -0.2(x - 30)
This is the form of a parabola with vertex (30,191).

The x term is squared so the parabola opens either up or down.
a. The -0.2 tells you that the parabola opens down.
=============
Found the problem--misplaced a decimal point.

b. -0.2x+12x + 11 = 0
Use the quadratic formula to solve
ax+bx+c=0
where
a=-0.2
b=12
c=11

x = [-b &#8730;(b-4ac)] / (2a)
= [-(12) &#8730;((12) - 4(-0.2)(11))] / 2(-0.2)
= [-12 &#8730;(152.8)] / -0.4
= 30 -30.903

x&#8330; = 30 + -30.903 &#8773; -1 invalid
x&#8331; = 30 - -30.903 &#8773; 61

Ticket sales increase until day 30, then decrease.

c. Tickets will stop selling during day 61, so ticket sales start on day 1, and stop 60 days later.

d. & e. y' = -0.4x + 12 = 0
-0.4x = -12
x = 30
Min/max occurs on day 30

y" = -0.4 < 0 so on day 30 ticket sales peak.

f. Ticket sales peak at 191 on day 30.

h. The solutions in this case are x=61 and x=-1. A quadratic equation always has two solutions (although the two may be identical).

i. x=-1 is an invalid solution because the day can't be negative.


Believe it or not, this is dumb math to me.


Whoa dude, you passed algebra? Crazy
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#8LimeSeahawkPosted 3/25/2013 12:30:51 AM
metalclash posted...
A trip to the emergency room can be a lot more than $100


Mine have a tendency to peak at about the $4000 area.
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#9lderivedxPosted 3/25/2013 4:08:28 AM
From: TMoney650 | #007
Whoa dude, you passed algebra? Crazy


That was brilliant.
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#10Net SharkPosted 3/25/2013 5:36:23 AM
Trick question: there is no solution because class canceled because of snow.
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