Terotrous posted...I'd have to see how you calculated it because my math should be mostly right (it doesn't account for the possibility of rolling a 31 on a non-passed stat, but that will only improve the odds).

I'm calculating chances of inheriting in worst case (first IVs to be inherited are paired ones). So:

M: vvvvxx

F: vvvxxv

Probability of first being perfect: 8 / 12 (2 / 3). Removing 2 perfect and 2 total.

v vvvxx

v vvxxv

Probability of second being perfect: 6 / 10 (3 / 5). Removing 2 perfect and 2 total.

vv vvxx

vv vxxv

Probability of third being perfect: 4 / 8 (1 / 2). Removing 2 perfect and 2 total. We have only unique pefect IVs at this point.

vvv vxx

vvv xxv

Probability of fouth being perfect: 2 / 6 (1 / 3). Removing 1 perfect and 2 total.

vvvv xx

vvvx xv

Probability of fifth being perfect: 1 / 4.

Cumulative probability for all 5 of them being perfect: (2*3*1*1*1)/(3*5*2*3*4) = 1/(5*3*4) = 1/60