-Zeke- posted...3.14
As per Koopa Algebra...
Wendy Larry Iggy (SMB3)
Lemmy Iggy Ludwig (SMW)
Lemmy Larry Wendy (NSMBW)
The remaining two configurations (NSMB2 and NSMBU) do not have definitive answers, for they contain nonlinear world orders. However, if we go by their "official" definitions:
Wendy Roy Morton (NSMB2)
Larry Lemmy Wendy (NSMBU)
As you can see, Wendy has the whopping 4 mentions, Larry and Lemmy both have 3, while Roy, Morton and Ludwig only got 1. This gives us the total of 6 possible outcomes for the 3-number Koopa pi. Meanwhile, Iggy, whose number is 2, will be driven crazy because he doesn't fit anywhere in our answer, and will thus cube himself in an attempt to become an 8, which Bowser Jr. is in all definitions starting from NSMBW. So yes, he will be going Boom Boom, and when the other Koopalings figure this out, so will they.
And remember, this was just the basic "main" formula. Don't get me even started on those side formulas that will only make things much more complicated.
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I'm up to my nipples in stupid Internet arguments.